X+x^2/2+2x^2-x

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Solution for X+x^2/2+2x^2-x equation: 


x in (-oo:+oo)

X+(x^2)/2+2*x^2-x = 0

X+5/2*x^2-x = 0

DELTA = (-1)^2-(5/2*4*X)

DELTA = 1-10*X

1-10*X = 0

1-10*X = 0 // - 1

-10*X = -1 // : -10

X = -1/(-10)

X = 1/10

DELTA = 0  <=>  t_1 = 1/10

x = 1/(2*5/2) i X = 1/10

x = 1/5 i X = 1/10

( x = ((1-10*X)^(1/2)+1)/(2*5/2) or x = (1-(1-10*X)^(1/2))/(2*5/2) ) i X > 1/10

( x = ((1-10*X)^(1/2)+1)/5 or x = (1-(1-10*X)^(1/2))/5 ) i X > 1/10

X-1/10 > 0

X-1/10 > 0 // + 1/10

X > 1/10

x in { 1/5, ((1-10*X)^(1/2)+1)/5, (1-(1-10*X)^(1/2))/5 }

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